C Programs

List Of All C Problems

Problem#1:
Find the sum of three numbers

/* Find the sum of three numbers */

#include
int main()
{
int num1 = 0;
int num2 = 0;
int num3 = 0;
int sum = 0;
printf(“Enter first number: ”);
scanf(“%d”,&num1);
printf(“Enter second number: ”);
scanf(“%d”,&num2);
printf(“Enter third number: ”);
scanf(“%d”,&num3);
sum = num1 + num2 + num3;
printf(“%d + %d + %d = %d\n”, num1, num2, num3, sum);
return 0;
}


//

Problem#2:
Take time in hour and convert it into seconds

/* Take time in hour and convert it into seconds */

#include
int main()
{
 int timeInHours=0; 
 int seconds=0;
 
 printf("Enter time in hours :");
 scanf("%d", &timeInHours);
 seconds=timeInHours*3600;
 printf("Seonds in %d hours=%d\n",timeInHours,seconds);
 return 0;
}


//

Problem#3:
Take quiz marks (out of 15) as input and find percentage

/* Take quiz marks (out of 15) as input and find percentage */

#include
int main()
{
float marksInCs102 = 0.0;
float percentage = 0.0;
printf(“Enter your CS102 quiz marks (out of 15)”);
scanf(“%f”,&marksInCs102);
percentage= (marksInCs102/15) * 100;
printf(“Your percentage in CS102 quiz is %f”, percentage);
return 0;
}
}


//

Problem#4:
Design a program to assist in the design of a hydroelectric dam. Prompt the user for the height
of the dam and for the number of cubic meters of water that are projected to flow from the
top to the bottom of the dam each second. Predict how many megawatts (1MW=10
6
W) of
power will be produced if 90% of the work done on the water by gravity is converted to
electrical energy. Note that the mass of one cubic meter of water is 1000kg.
Use 9.80 meters/seconds as the gravitational constant g.
The relevant formula (w=work, m=mass, g= gravity, h=height) is:
W=mgh

#include
int main()
{
 float height=0.0;
 float meters=0.0;
 float work=0.0;
 float mass=0.0;
 float gravity=9.80;
 float w=0.0;
 float power=0.0;
 float powerMegaWatt=0.0;
 
 printf("Enter dam height: ");
 scanf("%f", &height);
 printf("Enter num of cubic meters: ");
 scanf("%f", &meters);
 mass=meters*1000;
 work=mass*gravity*height;
 power=0.9*work;
 powerMegaWatt=power/1000000;
 printf("Power in Megawatts is %.3f", powerMegaWatt);
 
 
 return 0;
}


//

Problem#5:
Take computer file size in GB and display the size in bytes.

/* (1GB=1024 MB, 1MB=1024 KB, 1KB=1024 bytes) */

#include
int main()
{
 int fileSizeInGb=0;
 int bytes=0;
 
 printf("Enter fileSizeInGb :");
 scanf("%d", &fileSizeInGb);
 bytes=fileSizeInGb*1024*1024*1024;
 printf("%d Gb in bytes=%d\n",fileSizeInGb,bytes);
 return 0;
}



//

Problem#6:
Write a program that calculates time to fill the tank if the tank already has some
water. The initial and final readings of scale on the tank are used to calculate the total liters of
water added. It takes 8 seconds to add one liter of water to the tank. Display time in minutes.

/* 
Input: Initial scale reading: 23
Input: Final scale reading: 75
Output: Total time taken to fill the tank is 6.93 minutes
*/

#include
int main()
{
 float initialScaleReading=0.0;
 float finalScaleReading=0.0;
 float liters=0.0;
 float minutes=0.0;
 
 
 printf("Enter initialScaleReading:");
 scanf("%f", &initialScaleReading);
 printf("Enter finalScaleReading:");
 scanf("%f", &finalScaleReading);
 liters=finalScaleReading-initialScaleReading;
 minutes=liters*8/60;
 printf("Total time taken to fill the tank is %.2f minutes", minutes);
 
 
 return 0;
 
}


//

Problem#7:
Find whether a letter a capital letter or small letter

/* Find whether a letter a capital letter or small letter */

#include
 int main()
  { 
  char ch; 
  
  printf("Enter a letter: "); 
  scanf("%c" , &ch); 
  
  if( (ch >= 'a') && (ch <='z') ) 
  { 
  printf("\nThe letter you entered is a small letter\n ");
  } 
  else if( (ch >= 'A') && (ch <='Z') ) 
  { 
  printf("\nThe letter you entered is a capital letter\n ");
  } 
  else
  { 
  printf("\nThis is not an alphabet!\n"); 
  } 
  
 return 0; 
 }


//

Problem#8: An employee gets a yearly bonus only if his years of service are more than 3 years otherwise he gets no bonus. While years of service are more than 3 , bonus depends upon basic salary of employee. If salary is greater than or equals to 15000 than bonus is 20% of basic salary otherwise 15%.

#include
 int main()
 { 
  int yearsOfService = 0;
  float basicSalary = 0.0;
  float bonus = 0.0;
  
  printf("Enter employee's total years of service : "); 
  scanf("%d",&yearsOfService);
  
  if(yearsOfService > 3)
  { 
   printf("Enter employee's monthly basic salary : ");
   scanf("%f",&basicSalary);
   
   if(basicSalary >= 15000.00)
   { 
   bonus = basicSalary * .2; /* 20% bonus*/ 
   printf("Bonus is %.2f \n" , bonus);
   } 
   else 
   { 
   bonus = basicSalary * 0.15; /*15% bonus*/ 
   printf("Bonus is %.2f \n" , bonus); 
   }
 } 
 else 
 { 
  printf("Employee gets no bonus\n"); 
 }
 return 0;
}


//

Problem#9: Rock-paper-scissor game for 1 round only between player1 and player2

#include
int main()
{
 char player1;
 char player2;
 printf("Player 1's Choice :");
 scanf(" %c", &player1);
 printf("Player 2's Choice :");
 scanf(" %c", &player2);
 
 if((player1 == 'r') && (player2 == 'p'))
 {
  printf("Player 2 wins");
 }
 
 else if((player1 == 'r') && (player2 == 's'))
 {
  printf("Player 1 wins");
 }
 
 else if((player1 == 's') && (player2 == 'p'))
 {
  printf("Player 1 wins");
 }
 
 else if((player1 == 's') && (player2 == 'r'))
 {
  printf("Player 2 wins");
 }
 
 else if((player1 == 'p') && (player2 == 'r'))
 {
  printf("Player 1 wins");
 }
 
 else if((player1 == 'p') && (player2 == 's'))
 {
  printf("Player 2 wins");
 }
 
 else
 {
  printf("Match Draw");
 }

 return 0;
}


//

Problem#10: John needs a program to implement teacher’s discount policy. The program is to prompt the user to enter the purchase total and to indicate whether the purchaser is a teacher or not (y/n). If purchaser is not a teacher he/she will not get any discount. The store plans to give each customer a printer receipt, so your program is to create a nicely formatted output. Teachers receive a 13% discount on their purchases unless the purchase total is $100 or higher. The discount calculation occurs before addition of the 5% sales tax.

Example 1:
Total purchases $122.00
Teacher’s discount(13%) $15.86
Discounted total                      106.14
Sales tax (5%)                         5.31
Total $111.45

Example 2:
Total purchases $24.90
Sales tax (5%)         1.25
Total $26.15

#include
int main ()
{
 char teacher;
 float discountedTotal = 0.0;
 float totalPurchase = 0.0;
 float salesTax = 0.0;
 float teachersDiscounted = 0.0;
 float totalAmount = 0.0;
 
 printf("Are you a teacher? (y/n) :");
 scanf("%c", &teacher);

 if (teacher == 'y')
 {
  printf("Enter total amount of your purchase :$");
  scanf("%f", &totalPurchase);
  
  if(totalPurchase >= 100)
  {
   teachersDiscounted = totalPurchase * 0.13;   /* 13/100=0.13  13% discount */
   printf("Teacher's 13%% Discount is : $%.2f \n", teachersDiscounted);
   
   discountedTotal =  totalPurchase - teachersDiscounted;   
   printf("Discounted Total is : $%.2f \n", discountedTotal);
   
   salesTax = discountedTotal *  0.05;                /*5/100=0.5   5% sales Tax */
   printf("sale Tax 5%% amount is : $%.2f \n", salesTax);
   
   totalAmount=discountedTotal + salesTax;
   printf("Total Amount is : $%.2f ", totalAmount);
   
  }
  else
  {
   salesTax = totalPurchase * 0.05;
   printf("Sales Tax 5%% is : $%.2f", salesTax);
   
   totalAmount = totalPurchase + salesTax;
   printf("Total Amount is : $%.2f", totalAmount);
  }
  
 }
 
 else
 {
  printf("Enter total amount of your purchase :$");
  scanf("%f", &totalPurchase);
  
  salesTax = totalPurchase * 0.05; /* 5/100=0.5  5% sales Tax */
  printf("Sales Tax 5%% is : $%.2f \n", salesTax);
  
  totalAmount = totalPurchase + salesTax;
  printf("Total Amount is : $%.2f \n", totalAmount);
 }

 return 0;
}


//

Problem#11: Take distance in km as input and display the distance in m.

#include  
float calculateKmToM(float distInKm); /* function declaration */
int main ()
{
 float km = 0.0;
 float m = 0.0; 
 
 printf("Enter distance in kilometer :"); 
 scanf("%f" , &km);
 m = calculateKmToM(km); /* function calling */ 
 printf("Distance in meters is : %.2f" , m );
 return 0; 
} 
float calculateKmToM(float distInKm) 
{ 
 float distInM = 0.0; /* local variable declaration */ 
 distInM = distInKm * 1000;

 return distInM; 
}


//

Problem#12: Take time in hours as input and display the time in seconds.

#include
float timeInHours(float timeInHours);
int main(){
 float hrs=0.0;
 float secs=0.0;
 
 printf("Enter time in Hours :");
 scanf("%f" , &hrs);
 secs=timeInHours(hrs);
 printf("Time in Seconds is : %.1f", secs);
 return 0;
}

float timeInHours(float timeInHours){
 float secs=0.0;
 secs=timeInHours * 3600;
 return secs;
}


//

Problem#13: Take distance in km and time in hours as input and display the speed in km/hr.

#include
float calculateSpeed(float km, float hrs);
int main(){
 float km=0.0;
 float hrs=0.0;
 float speed=0.0;
 
 printf("Enter Distance in Km :");
 scanf("%f", &km);
 
 printf("Enter time in hours :");
 scanf("%f", &hrs);
 
 speed = calculateSpeed(km, hrs);
 printf("Speed is : %.1f", speed);
 return 0;
}
float calculateSpeed(float km, float hrs){
 float speed=0.0;
 speed = km/hrs;
 return speed;
}


//

Problem#14: Take distance in km and time in hours as input and display the speed in m/s.

#include
float calculateSpeed(float km, float hrs);
int main(){
 float km=0.0;
 float hrs=0.0;
 float speed=0.0;
 
 printf("Enter Distance is kilometers :");
 scanf("%f", &km);
 
 printf("Enter Time in hours :");
 scanf("%f", &hrs);
 
 speed = calculateSpeed(km, hrs);
 printf("Speed in m/s is : %.2f", speed);
 return 0;
}
float calculateSpeed(float km, float hrs){
 float speed=0.0;
 float m=0.0;
 float secs=0.0;
 m = km * 1000;
 secs = hrs * 3600;
 speed = m/secs;
 return speed;
}


//

Problem#15: Take temperature in Centigrade as input and convert it into Kelvin i.e. K = C + 273

#include
float convertInToKelvin(float centigrade);
int main(){
 float centigrade=0.0;
 float kelvin=0.0;
 
 printf("Enter Temperature in Centigrade :");
 scanf("%f", &centigrade);
 
 kelvin = convertInToKelvin(centigrade);
 printf("Temperature in Kelvin is : %.1f", kelvin);
}

float convertInToKelvin(float centigrade){
 float kelvin=0.0;
 kelvin = centigrade + 273;
 return kelvin;
}


//

Problem#16: Take temperature in Fahrenheit as input and convert it into Centigrade i.e. C = 5*(F-32)/9

#include
float converInToCentigrade(float fahrenheit);
int main(){
 float centigrade=0.0;
 float fahrenheit=0.0;
 
 printf("Enter Temperature in Fahrenheit :");
 scanf("%f", &fahrenheit);
 
 centigrade = converInToCentigrade(fahrenheit);
 printf("Temperature in Centigrade is %.1f", centigrade);
 return 0;
}
float converInToCentigrade(float fahrenheit){
 float centigrade=0.0;
 centigrade = 5 * (fahrenheit-32)/9;
 return centigrade;
}


//

Problem#17: Take temperature in Fahrenheit as input and convert it into Kelvin.

#include
float converInToKelvin(float fahrenheit);
int main(){
 float fahrenheit=0.0;
 float kelvin=0.0;
 
 printf("Enter Temperature in Fahrenheit :");
 scanf("%f", &fahrenheit);
 
 kelvin = converInToKelvin(fahrenheit);
 printf("Temperature in Kelvin is : %.2f", kelvin);
 return 0;
}
float converInToKelvin(float fahrenheit){
 float kelvin = 0.0;
 kelvin = (fahrenheit -32) * 5/9 + 273.15;
 return kelvin;
}


//

Problem#18: Get the least significant digit (right-most) of a 3-digit number.

#include
int leastSignificant(int threeDigitNum);
int main(){
 int threeDigitNum=0;
 int lsd=0;
 printf("Enter Three Digit Number : ");
 scanf("%d", &threeDigitNum);
 
 lsd = leastSignificant(threeDigitNum);
 printf("Least Significant digit is : %d", lsd);
 
return 0;
}
int leastSignificant(int threeDigitNum){
 int lsd=0;
 lsd = (threeDigitNum % 10);

return lsd;
}


//

Problem#19: Find out whether the input number is positive, negative or zero

#include
void positiveNegativeZero(int num);
int main(){

 int num=0;
 
 printf("Input any number :");
 scanf("%d", &num);
 
 num = positiveNegativeZero(num);

 
 return 0;
}

void positiveNegativeZero(int num){

 if (num > 0){
 printf("Number is Positive");
 return +num;
 }
 
 else if (num < 0){
 printf("Number is Negative");
 return -num;
 }
 
 else{
 printf("Number is Zero");
 return 0;
 }
 
}



//

Problem#20: Input four lengths a, b, c and d and find out whether they ‘can’ form a valid square. float distInKm float distInM CalculateKmToM

#include
void validSquare(int a, int b, int c, int d);
int main(){

 int a=0;
 int b=0;
 int c=0;
 int d=0;
 int square=0;
 
 
 printf("Enter Length A :");
 scanf("%d", &a);
 
 printf("Enter Length B :");
 scanf("%d", &b);
 
 printf("Enter Length C :");
 scanf("%d", &c);

 printf("Enter Length D :");
 scanf("%d", &d);
 
 square = validSquare(a,b,c,d);
 
 return 0;
}

void validSquare(int a, int b, int c, int d){

 int result=0;
 int square=0;
 
 if ((a==b) && (b==c) && (c==d)){
  
  printf("It's a Valid Square");
 }
 else{
  printf("It's not a Valid Square");
 }
 return square;
}


//

Problem#21: Two player guessing game

#include 
int main() 
{ 
 int number = 0, guess = 0; 
 int counter= 0; /*to count user attemps*/ 

 /* asking player1 to enter a number */ 
 printf("Player 1 !! enter a number between 1 to 10 :"); 
 scanf("%d" , &number); /* asking player2 to guess the number player1 entered */ 
 printf("Player 2 !! Guess the number: "); 
 scanf("%d" , &guess); while(guess != number) /* if player2 guessed wrong ask again */ 
 { 
  counter++; 
  printf("Wrong \n"); 
  printf("Player 2 !! Guess the number again.."); 
  scanf("%d",&guess); 
 } 
 printf("great!! u guessed after %d wrong attempts..", counter); 
return 0; 
}

//

Problem#22: Consider the next problem. We want to ask user to enter numbers and keep adding them until the user presses -1. We assumed -1 to be the stopping value. When user presses -1, loop stops and program shows total sum.

#include 
int main() 
{ 
 int num = 0, totalScore = 0; 
 printf("Enter number:"); /*input number*/ 
 scanf("%d",&num); while(num != -1) /*if num is not equal to sentinel value (stopping value which we assume is -1) */ 
 { 
  totalScore = totalScore + num; 
  printf("Enter number:"); 
  scanf("%d",&num);
 } 
 printf("Your total score is %d",totalScore); 

return 0; 
}

//

Problem#23: calculate percentage as long as the user wishes

#include 
int main() 
{ 
float marks =0.0; 
float percentage=0.0; 
char status = 'y'; /*we initialized status to 'y' , means yes , to indicate that the user wants to calculate percentage . if we do not initialize status with ‘y’ or ‘Y’ the loop will not even start*/ 

 /*check if status contains ‘y’ or ‘Y’*/ 
 while(status == 'y' || status == 'y') 
 { 
  printf("Enter your marks out of 500:"); /*input marks*/ 
  scanf("%f",&marks); 
  percentage = (marks /500) *100; 
  printf("Your percentage is %.2f \n", percentage); 
  
  /*ask user f wants to continue agian*/ 
  printf("Do you want to calculate percentage again? (y/n): "); 
  scanf(" %c" , &status); /*remember buffer problem in multiple character input? put a space before %c*/ 
  
 } 
 return 0; 
}

//

Problem#24: Program takes grade as input and comments according to it

#include  
int main () 
{ 
 char grade ;
 printf("Enter Your Grade: ");
 scanf("%c", &grade); /*Input grade */ 
 
 switch(grade) /*examine value in grade*/ 
 { 
   case 'A' : /* check if grade is equal to ‘A’*/ 
   printf("Excellent work!\n" ); 
   break; 
   
   case 'B' : /* check if grade is equal to ‘B’*/ 
   printf("Good Job!\n" ); 
   break; 
   
   case 'C' : /* check if grade is equal to ‘C’*/ 
   printf("Well done\n" ); 
   break; 
   
   case 'D' : /* check if grade is equal to ‘D’*/ 
   printf("You passed\n" ); 
   break; 
   
   case 'F' : /* check if grade is equal to ‘F’*/ 
   printf("Better try again\n" ); 
   break; 
   
   default : /*if no case matches run default block*/ 
   printf("Invalid grade\n" ); 
 } 
 return 0; 
 }

//

Problem#25: Modified version of above Program that takes grade as input and comments according to it. Now it works for both capital and small case

#include  
int main () 
{ 
 char grade ;
 printf("Enter Your Grade: ");
 scanf("%c", &grade); /*Input grade */ 
 
 switch(grade) /*examine value in grade*/ 
 { 
   case 'A' : /* check if grade is equal to ‘A’*/ 
   case 'a' :
   printf("Excellent work!\n" ); 
   break; 
   
   case 'B'  : /* check if grade is equal to ‘B’*/ 
    case 'b' :
   printf("Good Job!\n" ); 
   break; 
   
   case 'C'  : /* check if grade is equal to ‘C’*/
    case 'c' :
   printf("Well done\n" ); 
   break; 
   
   case 'D' : /* check if grade is equal to ‘D’*/
   case 'd' :   
   printf("You passed\n" ); 
   break; 
   
   case 'F' : /* check if grade is equal to ‘F’*/
   case 'f' :
   printf("Better try again\n" ); 
   break; 
   
   default : /*if no case matches run default block*/ 
   printf("Invalid grade\n" ); 
 }
 printf("Your grade is %c\n", grade );
 
 return 0; 
 }

//

Problem#26: Input two numbers. Ask user to enter a character +, -, * or / to choose the operation to perform among these numbers. Use switch statement to make a decision and, work and show result accordingly.

#include
int main()
{
 int num1=0;
 int num2=0;
 int sum=0;
 char process=0;
 char product=0;
 char subtract=0;
 char multiplication=0;
 char division=0;
 
 printf("Enter first Number :");
 scanf("%d", &num1);
 
 printf("Enter second Number :");
 scanf("%d", &num2);
 
 printf("Please Choice Any One of The Following Operations +,-,x,/ :");
 scanf(" %c", &process);
 
 
 switch(process)
 {
  case '+' :
   product = num1 + num2;
   printf("Sum Results : %d", product);
   break;
  case '-' :
   subtract = num1 - num2;
   printf("Subtraction Results : %d", subtract);
   break;
  case '*' :
   multiplication = num1 * num2;
   printf("Multiplication Results : %d", multiplication);
   break;
  case '/' :
   division = num1 / num2;
   printf("Division Results : %d", division);
   break;
  default :
   printf("Please Input Valid Operation");
 }
 
 return 0;
}


//

Problem#27: create a program that takes an alphabet as input and shows if it’s a vowel or not. Using while loop make sure that the input character is an alphabet. If not, ask user again to input character.

#include
int main()
{
 char alphabet;
 
 printf("Enter an Alphabet :");
 scanf(" %c", &alphabet);
 
 while ((alphabet < 65 ) || (alphabet > 122))
 {
  printf("~~Invalid Input~~ \n");
  printf("Please Input Valid Alphabet :");
  scanf(" %c", &alphabet);
 }
 

 switch (alphabet)
 {
  case 'a' :
  case 'A' :
   printf("Alphabet is Vowel");
   break;
 
  case 'e' :
  case 'E' :
   printf("Alphabet is Vowel");
   break;
  
  case 'i' :
  case 'I' :
   printf("Alphabet is Vowel");
   break;
  
  case 'o' :
  case 'O' :
   printf("Alphabet is Vowel");
   break;
  
  case 'u' :
  case 'U' :
   printf("Alphabet is Vowel");
   break;
  
  default :
   printf("Alphabet you Entered isn't Vowel");
 }
 return 0;
}


//

Problem#28: calculate percentage as long as the user wishes

#include
int main() 
{ 
 float marks =0.0, percentage=0.0; 
 char status = 0; 
 do 
 { 
  printf("Enter your marks out of 500:"); /*input marks*/ 
  scanf("%f",&marks); 
  percentage = (marks /500) *100; 
  printf("Your percentage is %.2f \n", percentage); /*ask user f wants to continue */ 
  printf("Do you want to calculate percentage again? (y/n): "); 
  scanf(" %c" , &status); /*remember buffer problem in multiple character input? put a space before %c*/ 
 } while(status == 'y' || status == 'Y'); 
 
 return 0; 
}


//

Problem#29: print tables of first five natural numbers

int main() 
{ 
 int i=0, j =0; 
 
 for(i=1 ; i<=5 ;i++) 
 { 
  printf("TABLE OF NUMBER %d\n" , i); 
  
  for(j = 1; j <= 10; j++) 
  { 
   printf("%d * %d = %d\n", i, j , i*j); 
  }   printf("\n"); 
 } 
 return 0; 
}

//

Problem#30: Design a program that is capable of calculating total of five subjects marks, each of 100 marks. The program will run as long as the user wishes but will work once at least without asking user’s permission.

#include
int main()
{
 int subMarks = 0;
 int subs = 0;
 int total = 0;
 char status = 0;
 
 do
 {
  total = 0;
  for(subs=1; subs<=5; subs++)
  {
  printf("Enter your total marks of subjects %d out of 100 :", subs);
  scanf("%d", &subMarks);
  
  
  
  while(subMarks > 100)
   {
   printf("~~Invalid Input~~ \n");
   printf("Please Enter your total marks of subject %d out of 100 :", subs);
   scanf("%d", &subMarks);
   }
   total = total + subMarks;
  }
  
  printf("Your Total Marks of 5 subjects is : %d \n", total); 
  
  printf("Do you want to Calculate your marks again? (y/n) :");
  scanf(" %c", &status);
 }
 
 while (status == 'y' || status == 'Y');
 
 
 return 0;
}


//

Problem#31: find maximum value in an array

#include 
int findMax (int arr[]);
int main()
{
 int array[10] ={} , maximum = 0, i = 0;

 printf("Enter 10 integers:\n" );
 for ( i = 0 ; i < 10 ; i++ )
 {
  scanf("%d", &array[i]);
 }
 maximum = findMax(array);
 printf("maximum element is %d.\n", maximum); 

 return 0;
}

int findMax (int arr[])
{
 int max=0, i=0;
 max = arr[0];
 for ( i = 1; i < 10; i++ )
 {
 if ( arr[i] > max)
  {
   max = arr[i];
  }
 }
return max;
}


//

Problem#33: Declare an array of char that holds vowels in small letters i.e. char vowel[5] = {‘a’ , ‘e’ , ‘I’ , ‘o’ , ‘u’} Create a function named capitalized that takes two parameters, first is the above mentioned array and second its size. This function changes all vowels to upper case. void capitalized (char arr[] , int size) Print array after capitalization Note: Use #define constant to set size of the array

/*

  vowel.c
  Written by Syed Rizwan Ali Shah

*/

#include
void capitalized (char arr[] , int size);
void printArray(int arr[], int size);
#define N 5     /* Taking constant of 5 */
int main()
{
    int size;
    char arr[N]={'a' , 'e' , 'i' , 'o' , 'u'};

    capitalized (arr ,size);

    return 0;
}
void capitalized (char arr[N] , int size)
{
    if (arr[0] == 'a')
    {
        size = 65;
        printf("Vowels in upper case are\n %c \t", size);
    }
    if (arr[1] == 'e')
    {
        size = 69;
        printf("%c \t", size);
    }
    if (arr[2] == 'i')
    {
        size = 73;
        printf("%c \t", size);
    }
    if (arr[3] == 'o')
    {
        size = 79;
        printf("%c \t", size);
    }
    if (arr[4] == 'u')
    {
        size = 85;
        printf("%c \t", size);
    }
}



/*
void capitalized (char arr[N] , int size)
{
    int i;

    if ((arr[N]== 'a' || 'e') && (arr[N] == 'i' || 'o') && (arr[N]== 'u'))
    {
        int i;
        for (i=0; i<5 data-blogger-escaped-are="" data-blogger-escaped-arr="" data-blogger-escaped-c="" data-blogger-escaped-case="" data-blogger-escaped-i="" data-blogger-escaped-in="" data-blogger-escaped-owels="" data-blogger-escaped-printf="" data-blogger-escaped-stdio="" data-blogger-escaped-upper="">

Problem#34: Write a program that creates emp.txt that contains 5 employee records. The data for each employee consist of : the employee’s id , pay for the week, 2% taxes deducted and net pay for the week. Take employee ids and pay input from the user. Tax and net pay will be calculated in the program. Then write this data to the file. Each record is a separate text line in file emp.txt. Followed by a blank line and write the information under each column heading. Your output will be some like:

/*


  Written by Syed Rizwan Ali Shah

*/

#include
int main()
{
    int id=0;
    int pay=0;
    int tax=0;
    int netPay=0;
    int i=0; /* variable for "for loop" */

    FILE *fptr;

    fptr = fopen("emp.txt","w"); 

    if(fptr == NULL)
    {
        printf("file not created");
    }

    else
    {
        /* Heading of all columns */
        fprintf(fptr,"Id \t");
        fprintf(fptr,"Pay \t");
        fprintf(fptr,"Tax \t");
        fprintf(fptr,"Net Pay \n");

        /* For loop, for multiple inputs */
        for (i=1; i<=5;i++)
        {

            /* Input for Employee's ID */
            printf("\n");           /* So user will be more comfortable in entering employee's ID and Employee's Pay */
            printf("Enter Employee No:%d's ID :", i);
            scanf("%d", &id);
            fprintf(fptr,"\n %d \t", id);


            /* Input for Employee's Pay */
            printf("Enter Employee No:%d's Pay :", i);
            scanf("%d", &pay);
            fprintf(fptr,"%d \t ", pay);


            tax = pay / 50;         /* tax calculation */
            netPay = pay - tax;

            fprintf(fptr, "%d \t", tax);
            fprintf(fptr, "%d \t \n", netPay);
        }
    }
    fclose(fptr);

    return 0;
}




//